Power driven diesel Thank you!!! Good to see your take on this. I am happy to see some familiar numbers.
I thought i could check myself and try to figure out what my current compound are producing. Doing so will help me gain confidence to properly size triples. My theory was both were too big just slightly, especially the D-Tech turbo unfortunately i couldn't get a smaller turbine housing like i did for the HT3B to see the effects it had. I think it would probably just push it closer to surge anyway.
Please let me know what you think about my calculations. I will post plotted compressor maps shortly too.
The Known Factors –
Turbos are Diesel Power Source D-Tech 62 (Known as stage 2, secondary, high pressure turbo or even manifold turbo) over a Borg Warner HT3B (Known as Stage 1, Primary, Atmospheric, or low pressure turbo)
My compound turbo produced total boost of 57 psig = 4.87 pressure ratio
Stage 1 atmospheric/low pressure turbo has produced 21 psig max = 2.42 PR
To figure out the boost and pressure ratio of second stage turbo, I have the total
PR of 4.87 or 57pisg
Stage 1 compressor is 21 psig or 2.42
Using 4.87 PR/2.42 PR= 2.012 PR = 2.0 PR 2nd STG turbo
So boost pressure would be 2.0 X 14.7 -14.7 = STG 2 turbo 14.7 psig
Turbo Boost Ratios
1st stage low pressure turbo 21 psig
Stage 2 turbo 14.7 psig
21/14.7 = 1.42:1 ratio low pressure turbo is overdriving second stage turbo
EGT’s max 1297
Max RPM 3000
Drive Pressure
Max total boost 57 psig Max drive psig 69 69/57 = 1.21:1 ratio for drive pressure.
To improve engine breathability low pressure turbo should now be waste gated for increased top rpm HP to maintain 1:1 drive pressure ratio.
*New triple turbo might also improve idle haze as drive pressure is high at idle now b/c of the smallest available low pressure turbo (HT3B) turbine housing is now installed, 0.6 psig at idle. Drive pressure tends to be higher until low pressure turbo spools or steady heavy load is applied. Boost is 0.3 psig at idle. When under steady load drive ratio is just above or at 1:1. Drive psi at idle when cold engine is 1psig (thick cold oil)
Compressor Flow Calculations
For most outlet temperature and density ratio calculations, I can calculate separately if I feel crazy enough to do so lol. I am using density ratio table and compressor discharge temperature tables for the following formulas. The known information is:
Calculate Engine Air Flow requirements
Air Flow in CFM = CID X RPM X .5 X VE / 1728
RPM = 3000 CID = 361 VE = 90%
361 X 3000 X .5 X .90/1728 = 282 CFM air flow required before turbo charging
282 X .076 to convert to pounds per minute of air = 21.43 lbs of air
Calculating Air Flow Requirements of Stage 2 Compressor First
Information 21 lbs of air X stage 2 compressor density ratio. Stage 2 compressor has a 2.0 PR
Assumed 72% compressor efficiency
Using the table = 1.5 density ratio with 90-degree ambient inlet air outlet temp is 250 F
21 lbs of air X density ratio of 1.5 = 32.1 lbs per minute of air @ 2.0 PR is what the stage 2 compressor must flow
Confirmed D tech 62 turbo is operating at 74% for required output.
Stage 1 turbo Assume 75% efficiency at 2.42 PR ambient air 90 degrees F outlet air temp is 290 F
Density ratio is 1.7 X stage 2 air flow requirement of 32.1 lbs air = 1.7 X 32.1 = 57.7 lbs per min required air flow for stage 1 low pressure turbo.
Confirmed Borg Warner HT3B turbo is operating at 74% efficiency with 54.7 lbs per minute of air @ 2.42 pressure ratio.
Correcting stage 2 turbo density ration calculation
Because inlet air temperature is no longer close to 90 degrees Fahrenheit. It is now the outlet temperature of the stage 1 turbo which is 290 degrees.
Forced to calculate long head because no density table exists with ambient temperature as high as 290 degrees.
DR = (T1c/(T1c+(((T1c x PR.283) – (T1c)/CE)) x PR
T1c = original ambient inlet temperature in degrees Raken. (290 degrees F stage 1 outlet temp + 460 = 750 degrees R)
PR = 2.0 CE = Compressor efficiency – checked compressor map, found for 32.1 pounds of air at a 2.0 PR the compressor was actually more efficient than originally assumed. New compressor efficiency is 74%.
(750/(750+(((750 x 2.0 .283) – 750) / .74%))) x 2
(750/(750+(((750 x 1.216) -750)/.74))) x 2
(750/(750 + ((912-750)/.74))) x 2
(750/750+(162/.74))) x 2
(750/(750+218.91)) x 2
(750/968.918) x 2
.774 x 2 = 1.54 DR corrected for STG2 turbo
*Not much changed for the Density ratio, though a tiny chart is hard to eyeball and I think I did just round down so not too surprised.
Corrected Compound turbo air flow calculations
Base engine air flow requirement was: 21.43 lbs air per minute
21.43 x corrected DR STG2 turbo= 21.43 x 1.54=33Lbs of air a minute, required air from STG 2
33lbs air* STG 1 turbo DR= Stg 1 air flow
33 x 1.7= 56.1lbs of air per minute corrected air flow produced from STG 1 turbo.
Determine inter cooler inlet/outlet temp and density ratio
*Note: I have a Spearco intercooler rated at 1100 cfm and 1 psi pressure drop. Cannot find spec for efficiency, would have to contact factory.
I do have intercooler inlet and outlet temperature sensors installed on my truck. I can recall approximate temperatures of at max power testing of 290 degrees F at full throttle inlet and approximately 130 degrees F outlet.
Finding intercooler efficiency based on above information:
290-130=160 temperature drop on a 60 degree F day when testing occurred
TE= Thermal efficiency of intercooler – unknown
Tcharge= Intercooler inlet temp - 290 degrees F
Coolant = Outside ambient air temperature – 60 degrees F
TE= Tdrop/(Tcharge – coolant)
160/(290 -60)
160/230= .69 % intercooler efficiency
I will use 65% efficiency to error on the conservative side. Also the above tests were noted at 60 degrees F whereas everything calculated so far is based on 90 degree ambient air.
Calculate Intercooler Inlet Temperature
Hot air left STG 1 @ 290 degrees F and entered STG 2 inlet
Actual turbo temperature rise of STG 2
T2C = New compressor outlet temp degrees Rankin = unknown
T1C = Original inlet absolute degrees R = 460 + 290 = 750 R
PR = Pressure ratio = 2.0
CE = Compressor efficiency New corrected efficiency is 74%
T2C = T1C (((T1C X PR .283) – TC1)/CE)
750 +(((750 x 2 .283)-750)/.74)
750+(((75 x 1.216)-750/.74)
750+((912.541-750)/.74
750+((162.54/.74)
750+219.651
T2C=969.65 -460 =509 degree F air leaving stage 2 compressor headed for intercooler
Final Inter Cooler Calculations
From calculated above intercooler efficiency is 69% I will use 65% to error on the conservative side. 590 degerees F x .65 = 330.8 intercooler will remove from charge air temperature
509-331 = 178 degrees leaving intercooler into engine
IC = density change from temperature change through intercooler
T1 = original temperature degrees Rankin leaving compressor stage two 509+460=969 degrees R
T2= New intercooler temperature leaving intercooler degrees R 178+460=638 degrees R
IC = (T1/T2)-1
(969/638)-1=1.51 -1 =.51
Density increase of 1.51 = a 51% increase in air density
Total engine airflow is 56.1 x intercooler density ratio of 1.51 = 84.71 lbs/minute entering the engine or 84.71/.076 = 1114.06 cfm at 57 psi total boost